Let Tr be the rth term of an AP, for r=1, 2…. . If for some positive integers m and n, we have Tm=1n and Tn=1m, the Tm+n equal
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a
1mn
b
1m+1n
c
1m
d
0
answer is C.
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Detailed Solution
Let a be the first term and d be the com-mon difference of the given A.P. Then according to thehypothesis, Tm−Tn=1n−1m⇒ (m−n)d=m−nmn⇒d=1mn.⇒ Tm+n−Tm=(m+n−m)1mn=1m