Let Tr be the rth term of an AP, for r=1, 2…. . If for some positive integers m and n, we have Tm=1n and
Tn=1m, the Tm+n equal
1mn
1m+1n
1m
0
Let a be the first term and d be the com-mon difference of the given A.P. Then according to the
hypothesis,
Tm−Tn=1n−1m⇒ (m−n)d=m−nmn⇒d=1mn.⇒ Tm+n−Tm=(m+n−m)1mn=1m