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Let Tr be the rth term of an AP, for r=1, 2…. . If for some positive integers m and n, we have Tm=1n and

 Tn=1m, the Tm+n equal 

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1mn
b
1m+1n
c
1m
d
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detailed solution

Correct option is C

Let a be the first term and d be the com-mon difference of the given A.P. Then according to thehypothesis,        Tm−Tn=1n−1m⇒ (m−n)d=m−nmn⇒d=1mn.⇒ Tm+n−Tm=(m+n−m)1mn=1m


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