Q.

Let tr denotes the rth term in the binomial expansion of (1+a)50 .  If t25+t27=12552t26 Then sum of all possible values of a is

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a

32

b

2

c

52

d

12

answer is C.

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Detailed Solution

We havetr+1tr= 50Crar 50Cr−1ar−1=51−rra       Nowt25t26+t27t26=12552⇒2625a+25a26=12552⇒2526a2-12552a+2625=0 Sum of all possible values of a is 12552×2625=52
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Let tr denotes the rth term in the binomial expansion of (1+a)50 .  If t25+t27=12552t26 Then sum of all possible values of a is