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Let the tangents drawn from the origin to the circle, $x^{2} + y^{2} - 8 x - 4 y + 16 = 0$ touch it at the points A and B. Then ${(A B)}^{2}$ is equal to:

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detailed solution

Correct option is A

Length of tangent=L=S1=16=4Radius of the circle=R=16+4−16=2∴Length of Chord of contact =2LRL2+R2=2×4×216+4=1620⇒Square of length of chord of contact =645

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Let the tangents drawn from the origin to the circle, x2+y2−8x−4y+16=0 touch it at the points A and B. Then AB2 is equal to:

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Let the tangents drawn from the origin to the circle, $x^{2} + y^{2} - 8 x - 4 y + 16 = 0$ touch it at the points A and B. Then ${(A B)}^{2}$ is equal to: