Let two points be A(1,-1) and B(0,2) . If a point Px',y' be such that the area of ΔPAB=5 sq units and it lies on the line 3x+y-4λ=0, then a value of λ is :

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-3

answer is B.

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Detailed Solution

Area=120211-11x'y'1=5⇒-21-x'+y'+x'=±10⇒-2+2x'+y'+x'=±10⇒3x'+y'=12 or 3x'+y'=-8⇒λ=3,-2

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