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Let $U$ be a Universal set and $n (U) = 12 .$ If $A, B \subseteq U$ are such that $n (B) = 6$ and $n (A \cap B) = 2$ then $n (A \cup B')$ is equal to

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Correct option is D

n(A∪B')=n(A)+n(B')-n(A∩B')=n(A)+n(U)-n(B)-(n(A)-n(A∩B)) =n(U)-n(B)+n(A∩B) =12-6+2=8.

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Let U be a Universal set and n(U)=12. If A,B⊆U are such that n(B)=6 and n(A∩B)=2 then n(A∪B') is equal to

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Let $U$ be a Universal set and $n (U) = 12 .$ If $A, B \subseteq U$ are such that $n (B) = 6$ and $n (A \cap B) = 2$ then $n (A \cup B')$ is equal to