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Let U be the universal set and . Then [(AB)(BC)(CA)] equals

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a
A∪B∪C
b
A∩B∩C
c
A∪(B∩C)
d
A∩(B∪C)

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detailed solution

Correct option is B

A−B→ Regions 3 and 5.B−C→Regions 2 and 6.C−A→Regions 4 and 7.∴ (A−B)∪(B−C)∪(C−A)→Regions2,3,4,5,6,7∴ [(A−B)∪(B−C)∪(C−A)]′→Region 1, which is A∩B∩C

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