Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Let u^=u1i^+u2j^+u3k^ be a unit vector in ℝ3 and ω^=16(i^+j^+2k¯). Given that three  exists a vector v→ in ℝ3 such that |u^×v→|=1 and  w.^(u^×v→)=1 which of the following  statement(s) is (are) correct?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

There is exactly one choice for such v→

b

There are infinitely many choices for such v→

c

if u^ lies in the xy plane then u1=u2

d

if u^ lies in the xz plane then 2u1=u3

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

u=1,w=1,u×v=1⇒vsinu,v=1w.^u^×v→=1⇒wu×vcosw,u×v=1⇒cos ω,u×v=1hence w^ is perpendicular to both u^ and v→  As it is given there exists a vector v→ ⇒w^ must be ⊥ to u^hence infinitely many such v→ existsif u^=u1i^+u2j^  and  u^.w^=0 ⇒u1+u2=0⇒u1=u2if u^=u1i^+u3k^ and  u^.w^=0 ⇒u1+2u3=0⇒u1=2u3
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring