Let V→=2i^+j^−k^ and W→=i^+3k^. If U→ is a unit vector, then the maximum value of the scalar triple product[U→V→W→] is
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a
-1
b
10+6
c
59
d
60
answer is C.
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Detailed Solution
Given that V→=2i^+j^−k^ and W→=i^+3k^ and U→ is a unit vector|U→|=1 Now, [U→V→W→]=U→⋅(V→×W→) =U→⋅(2i^+j^−k^)×(i^+3k^)=U→⋅(3i^−7j^−k^)=32+72+12cosθ which is maximum when cosθ=1