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  Let V=2i^+j^k^ and W=i^+3k^. If U is a unit vector, then the maximum value of the scalar triple product[UVW] is 

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a
-1
b
10+6
c
59
d
60

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detailed solution

Correct option is C

Given that V→=2i^+j^−k^ and W→=i^+3k^ and U→ is a unit vector|U→|=1 Now,  [U→V→W→]=U→⋅(V→×W→)                            =U→⋅(2i^+j^−k^)×(i^+3k^)=U→⋅(3i^−7j^−k^)=32+72+12cos⁡θ which is maximum when cos⁡θ=1


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If a=i^+j^,b=j^+k^,c=k^+i^ then in the reciprocal system of vectors a,b,c  reciprocal of vector ais 


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