Let the volume of a parallelepiped whose coterminous edges are given by u→=i^+j^+λk^,v→=i^+j^+3k^, and w→=2i^+j^+k^, be 1 cu.unit. If θ be the angle between the edges u→ and w→, then cosθ can be:
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
763
b
766
c
57
d
533
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Volume of parallelepiped formed by coterminous vectors a¯,b¯,c→ is [a¯b¯c→]∴±1=11λ113211⇒=-λ+3=±1⇒λ=2 or λ=4 For λ=2,cosθ=2+1+266=56 For λ=4,cosθ=2+1+4618=763
Let the volume of a parallelepiped whose coterminous edges are given by u→=i^+j^+λk^,v→=i^+j^+3k^, and w→=2i^+j^+k^, be 1 cu.unit. If θ be the angle between the edges u→ and w→, then cosθ can be: