Let A=1 a0 1, where a>0, Sum of the
series S = trace (A) + trace12A+trace122A2+trace123A3+ … is
3
4
6
8
A=I+B, where B=0 a0 0
B2=O we get Br=O ∀r≥2
Ar=(I+B)r=I+rB=1ra01 ∀r≥1
trace 12rAr=12r(2)=12r−1 ∀r≥1.
S=2+1+122+123+⋯=21−12=4