Q.
Let x be the number of 5 digit numbers sum of whose digits is even and y be the number of 5 digit numberssum of whose digits is odd, then
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a
x=y
b
x+y = 90,000
c
x= 45,000
d
x < y
answer is A.
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Detailed Solution
x =9 x 10 x 10 x 10 x 5 = 45000Similarly y= 45,000x = y & x+y= 90,000
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