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Q.

Let x be the number of 5 digit numbers sum of whose digits is even and y be the number of 5 digit numberssum of whose digits is odd, then

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a

x=y

b

x+y = 90,000

c

x= 45,000

d

x < y

answer is A.

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Detailed Solution

x =9 x 10 x 10 x 10 x 5 = 45000Similarly y= 45,000x = y & x+y= 90,000
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Let x be the number of 5 digit numbers sum of whose digits is even and y be the number of 5 digit numberssum of whose digits is odd, then