Let {x} denote the fractional part of x. Then limx→0{x}tan{x}is equal to

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-1

Does not exist

answer is D.

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Detailed Solution

L.H.L= limx→0−{x}tan{x}=limx→0−x−[x]tan(x−[x]) = limx→0−x+1tan(x+1)=1tanx R.H.L. =limx→0−x−[x]tan(x[x])=limx→0xtanx=1 ∴L.H.L≠R.H.L.

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