Questions
Let .The value of is equal to
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a
log12secx2+1+C
b
log sec x2+12+C
c
12log sec x2+1+C
d
None of the above
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Correct option is B
We have, ∫x2sin x2+1−sin 2x2+12sin x2+1+sin 2x2+1dx=∫x2sin x2+1−2sinx2+1⋅cos x2+12sin x2+1+2sinx2+1⋅cos x2+1dx=∫x1−cos x2+11+cos x2+1dx=∫xtan x2+12dx=∫tan x2+12dx2+12=log sec x2+12+CSimilar Questions
The value of is equal to
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