First slide
Methods of integration
Question

Let x21,nN.The value of x2sin x2+1sin 2x2+12sin x2+1+sin 2x2+1dx is equal to 

Moderate
Solution

We have, x2sin x2+1sin 2x2+12sin x2+1+sin 2x2+1dx

=x2sin x2+12sinx2+1cos x2+12sin x2+1+2sinx2+1cos x2+1dx=x1cos x2+11+cos x2+1dx=xtan x2+12dx=tan x2+12dx2+12=log sec x2+12+C

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