Let x2≠nπ−1,n∈N . If ∫x2sinx2+1−sin2x2+12sinx2+1+sin2x2+1dx=lnf(x)+C then sec−1f(1) equals
Let x2+1=t⇒xdx=dt2
Given integral =12∫2sint−2sintcost2sint+2sintcostdt
=12∫tant2dt=lnsect2+C∴f(x)=secx2+12sec−1f(1)=1