First slide
Relations XII
Question

Let X = {1, 2, 3, 4}. The number of equivalence relations that can be defined on X is

Moderate
Solution

The number of equivalence relations 

Bkn=0k-1k-1nBn;   B0=1 , B1=1, B2=2 ,B3=5

B4=30B0+31B1+32B2+33B3

= 1 + 3 + 3 ×2 + 1 × 5 = 15

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