Let x= sin 1o, then the value of the expression 1cos⁡0∘⋅cos⁡1∘+1cos⁡1∘⋅cos⁡2∘+1cos⁡2∘⋅cos⁡3∘+⋯+1cos⁡44∘⋅cos⁡45∘=

1sin⁡1∘sin⁡1∘−0∘cos⁡0∘cos⁡1∘+sin⁡2∘−1∘cos⁡1∘cos⁡2∘+sin⁡3∘−2∘cos⁡2∘cos⁡3∘+⋯+sin⁡45∘−44∘cos⁡44∘cos⁡45∘=1sin⁡1∘tan⁡1∘+tan⁡2∘−tan⁡1∘+tan⁡3∘−tan⁡2∘+tan⁡4∘−tan⁡3∘+⋯+tan⁡45∘−tan⁡44∘=1sin⁡1∘=1x