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Questions  

 Let x=sin10 then the value of 1cos00cos10+1cos10cos20++1cos440cos45°=

a
2x
b
x2
c
1x
d
x

detailed solution

Correct option is C

We have1sin10sin10cos10+sin20-10cos10cos20+………+sin45°-440cos440cos410=1sin10tan10+tan20-tan10+tan30-tan20+………tan45°-tan440=1x

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