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Let Δ=142012512x5x2 Solution set of   = 0 is

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a
{−2,3}
b
{−3,4}
c
{4,−6}
d
{−2,−1}

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detailed solution

Correct option is D

Applying R2→R2−R1,R3→R3−R1 we getΔ=1−42002−1502(x+2)5x2−4=2(x+2)1−1515(x−2)     =10(x+2)(x+1)Now,     Δ=0⇒x=−2,−1


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