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Let $Δ (x, y) = |\begin{array}{ccc} 1 & x & y \\ 1 & x + y & y \\ 1 & x & x + y \end{array}|$ .Then $Δ (- 3, 2)$ equal to

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Correct option is B

Using R2→R2−R1,R3→R3−R1 we getΔ(x,y)=1 x y0 y 00 0 x=xy∴ Δ(−3,2)=−6

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Let Δ(x,y)=1xy1x+yy1xx+y .Then Δ(−3,2) equal to

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Let $Δ (x, y) = |\begin{array}{ccc} 1 & x & y \\ 1 & x + y & y \\ 1 & x & x + y \end{array}|$ .Then $Δ (- 3, 2)$ equal to