Q.
Let x2+y2+xy+1≥a(x+y)∀x,y∈R, then the number of possible integer(s) in the range of a is________.
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answer is 3.
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Detailed Solution
x2+x(y−a)+y2−ay+1≥0x∈R ⇒ (y−a)2−4y2−ay+1≤0⇒ −3y2+2ay+a2−4≤0∴ 3y2−2ay+4−a2≥0 y∈R D≤0⇒ 4a2−4,34−a2≤0⇒ a2−34−a2≤0⇒4a2−12≤0∴ Range of a∈(−3,3)⇒ number of integer {−1,0,1}
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