Let A=x,y,z, B=u,v,w and f:A→B be defined by f(x)=u, f(y)=v, f(z) = w. Then f is
surjective but not injective
injective but not surjective
bijective
None of the above
A={x,y,x}, B={u,v,w} Now, f :A→B
f is one -one and f is onto.