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$Let y = y (x) be the solution of the D.E \sin x \frac{d y}{d x} + y \cos x = 4 x, x \in (0, π) . If$ $\Rightarrow y (π / 2) = 0 then y (π / 6) is$

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Correct option is D

∫d(ysinx)=∫4x⇒ysinx=2x2+c passes through (π2,0)⇒c=−π22 ysinx =2x2−π22⇒ put x=π6⇒y2=2⋅π236−π22⇒y=−8π29

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Let y=y(x) be the solution of the D.E sin⁡xdydx+ycos⁡x=4x,x∈(0,π). If ⇒y(π/2)=0 then y(π/6) is

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$Let y = y (x) be the solution of the D.E \sin x \frac{d y}{d x} + y \cos x = 4 x, x \in (0, π) . If$ $\Rightarrow y (π / 2) = 0 then y (π / 6) is$