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Questions  

 Let z be a complex number such that z-iz+2i=1 and |z|=52, Then the value of z+3i is: 

a
10
b
23
c
154
d
72

detailed solution

Correct option is D

Given |z-i|2=|z+2i|2    ⇒x2+(y-1)2=x2+(y+2)2⇒-2y+1=4y+4⇒y=-12 Given |z|=52    It gives      x2+y2=254x2=244=6x=±6 It gives z=±6-i2 The required value is |z+3i|=6+5i2=6+254=∣72

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