First slide
Algebra of complex numbers
Question

 Let z be a complex number such that z-iz+2i=1 and |z|=52, Then the value of z+3i is: 

Moderate
Solution

 Given |z-i|2=|z+2i|2    x2+(y-1)2=x2+(y+2)2-2y+1=4y+4y=-12 Given |z|=52

    It gives 

     x2+y2=254x2=244=6x=±6

 It gives z=±6-i2 The required value is |z+3i|=6+5i2=6+254=72

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