Let z be a complex number such that Z = 2 then maximum possible value of z+2z is
1
2
3
4
Let z=2(cosθ+isinθ).Now
z+2z=2(cosθ+isinθ)+(cosθ−isinθ)
=3cosθ+isinθ
⇒z+2z2=9cos2θ+sin2θ
=1+4(1+cos2θ)≤9
∴ maximum possible value of z+2z is 3 which
is attained when z = 1