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$Let z \in C, if A = \{z : \arg (z) = \frac{π}{4}\} and B = \{z : \arg (z - 3 - 3 i) = \frac{2 π}{3}\} then$ $n (A \cap B) is equal to$

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Correct option is D

Argz=π4⇒Tan−1yx=π4⇒y=x (x>0,y>0)arg (z−3−3i)=2π3 Tan−1y−3x−3=2π/3y−3=−3x−3y−3>0,x−3<0We can observe that 3+3i∈A but ∉B∴nA∩B=0

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Let z∈C , if A=z:arg(z)=π4 and B=z:arg(z-3-3i)=2π3 then n(A∩B) is equal to

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$Let z \in C, if A = \{z : \arg (z) = \frac{π}{4}\} and B = \{z : \arg (z - 3 - 3 i) = \frac{2 π}{3}\} then$ $n (A \cap B) is equal to$