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Q.

Let z=11−2i3+5i1+2i−510i3−5i−10i11, then

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a

z is purely imaginary

b

z is purely real

c

z=0

d

none of these

answer is B.

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Detailed Solution

Conjugate of zequals the determinant obtained by taking conjugate of each of its element. Therefore,z¯=11+2i3−5i1−2i−5−10i3+5i10i11=11−2i3+5i1+2i−510i3−5i−10i11=zThus, z is purely real.
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