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Questions  

 Let z1, z2 be two complex numbers such that z10  and z2/z1 1 is purely real, then 2iz1+5z22iz15z2 is equal to

 

a
3
b
2
c
1
d
0

detailed solution

Correct option is C

Suppose  z2/z1=a,where a∈R Now, , 2iz1+5z22iz1−5z2=2i+5z2/z12i−5z2/z1=2i+5a2i−5a=1

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