lf A, B, c are angles of a triangle, then 2sin⁡A2cosec⁡B2sin⁡C2−sin⁡Acot⁡B2−cos⁡A is

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independent of A, B, C

function of A, B

function of C

none of these

answer is A.

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Detailed Solution

2sin⁡A2cosec⁡B2sin⁡C2−cos⁡A2cos⁡B2−cos⁡A =2sin⁡A2cosec⁡B2×cos⁡A+B2−cos⁡A2cos⁡B2−cos⁡A=2sin⁡A2cosec⁡B2−sin⁡A2sin⁡B2−cos⁡A =−2sin2⁡A2−cos⁡A=−1

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