Q.
lf a, b, c are pth, qth and rth terms of a GP, then (q - r) log a + (r - p) log b + (p - q) log c is equal to
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a
p+q+r
b
1
c
-pqr
d
0
answer is D.
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Detailed Solution
Let A and R be the first term and common ratio of the given GP. Then, a = ARP-1⇒loga=logA+(p−1)logR-----isimilarly, logb=logA+(q−1)logR----iiand logc=logA+(r−1)logR-----iiinow , (q - r) log a + (r - p) log b + (p - q) log c=(q−r){logA+(p−1)logR}+(r−p){logA+(q−1)logR}+(p−q){logA+(r−1)logR} =logA[q−r+r−p+p−q]+logR[p(q−r)+q(r−p)+r(p−q)−(q−r)−(r−p)−(p−q)] =logA⋅0+logR⋅0=0
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