lf a + b + c=0, then the roots of the equation 4ax2+3bx+2c=0 are
equal
imaginary
real
None of these
Given, a, + b + c=0 ………………..(i)and 4ax2+3bx+2c=0∵D=b2−4ac∴D=(3b)2−4(4a)(2c)=9b2−32ac=9(a+c)2−32ac [∵ from Eq. (i) ]=9(a−c)2+4ac>0Hence, roots are real.