lf f(x) is a function satisfying f1x+x2f(x)=0 for all non-zero x, then ∫sinθcosecθ f(x)dx is equal to
sinθ+cosecθ
sin2θ
cosec2θ
None of these
we have, f1x+x2f(x)=0⇒f(x)=−1x2f1x
I=∫sinθcosecθ f(x)dx=∫sinθcosecθ −1x2f1xdx=∫cosecθsinθ f(t)dt, where t=1x⇒I=−∫sinθcosecθ f(t)dt=−I⇒2I=0⇒I=0