First slide
Evaluation of definite integrals
Question

lf f(x) is a function satisfying f1x+x2f(x)=0 for all non-zero x, then  sinθcosecθf(x)dx is equal to

Difficult
Solution

we have, f1x+x2f(x)=0f(x)=1x2f1x

I=sinθcosecθf(x)dx=sinθcosecθ1x2f1xdx=cosecθsinθf(t)dt, where t=1xI=sinθcosecθf(t)dt=I2I=0I=0

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