lf n > 0 and exactly 15 integers satisfy (x+6)(x−4)(x−5)(2x−n)≤0 then sum of digits of the least possible value of n is

(x+6)(x−4)(x−5)(2x−n)≤0Hence, x∈[−6,4]∪5,n2Now, there are 11 integers in [-6, 4].So, there must be 4integers in 5,n2So, n2∈[8,9)⇒ n∈[16,18)