Questions
lf points and are collinear, then
a
1a2+1b2=1
b
1a+1b=1
c
a2+b2=1
d
none of these
detailed solution
Correct option is A
Given points are collinear∴a2010b21111=0⇒a2b2−1+0−b2=0⇒a2b2=a2+b2⇒1a2+1b2=1Talk to our academic expert!
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Consider a point where m and n are positive integers.B is the reflection of A in the line is the reflection of B in the y-axis, D is the reflection of C in the x-axis and E is the reflection of D in the y-axis. The area of the pentagon is
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