A light ray coming along the line 3x + 4y = 5 gets reflected from the line ax + by = 1 and goes along the line 5x - 12y = 10. Then,
a=64/115,b=112/15
a=14/15,b=−8/115
a=64/115,b=−8/115
a=64/15,b=14/15
ax + by = 1 will be one of the bisectors of the given lines
Equations of bisectors of the given lines are
3x+4y−55=±5x−12y−1013
or 64x−8y=115
or 14x+112y=15
or a=64115,b=−8115
or a=1415,b=12115