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A light ray reflected from $x = - 2 . If the reflected ray$ $touches the circle x^{2} + y^{2} = 4 and the point of incident is$
$(- 2, - 4), then the equation of incedents ray$

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a

4y+3x+22=0

b

3y+4x+20=0

c

4y+2x+20=0

d

y+x+6=0

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detailed solution

Correct option is A

Any tangent of x2+y2=4 is y=mx±21+m2 . If it passes through (−2,−4), then (2m−4)2=41+m2 or 4m2+16−16m=4+4m2 or m=∞,m=34Hence, the slope of the reflected ray is 3/4. Thus, the equation of the incident ray is (y+4)=−34(x+2) i.e., 4y+3x+22=0

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