A light ray reflected from x=−2 . If the reflected ray  touches the circle x2+y2=4 and  the point of incident is (−2,−4) , then the equation of incedents ray

Any tangent of x2+y2=4 is y=mx±21+m2 . If it  passes through (−2,−4), then (2m−4)2=41+m2 or 4m2+16−16m=4+4m2  or  m=∞,m=34Hence, the slope of the reflected ray is 3/4. Thus, the equation of the incident ray is (y+4)=−34(x+2) i.e., 4y+3x+22=0