First slide
Introduction to limits
Question

limmcosxmm is equal to

Moderate
Solution

limmcosxmm=limm1+cosxm1m=limm11cosxmm=limm12sin2x2mm=elimmm2sin2x2nlim-2msinx2mx22x24m2m=e=e2limmx24m=e0=1

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