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$\lim_{n \to \infty} (\frac{1^{m} + 2^{m} + 3^{m} + .... + n^{m}}{n^{m + 1}}) =____$

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Correct option is A

limn→∞1m+2m+3m+…+nmnm+1=limn→∞1n1mnm+2mnm+….+nmnm=limn→∞⁡1n∑r=1n rnm=∫01 xmdx=xm+1m+101=1m+1−0m+1=1m+1

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limn→∞1m+2m+3m+....+nmnm+1=____

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Ready to Test Your Skills?

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$\lim_{n \to \infty} (\frac{1^{m} + 2^{m} + 3^{m} + .... + n^{m}}{n^{m + 1}}) =____$