limn→∞n2(1−cos1n)(1−cos1n)(1−cos1n)... to ∞ equals

Ltn→∞n2(1−cos1n)(1−cos1n).....∞y=(1−cos1n)(1−cos1n).....∞y2=(1−cos1n)y⇒y=1−cos1nLtn→∞n2(1−cos1n)=Lt1n→01−cos1n(1n)2=12