limn→∞ 11−n2+21−n2+31−n2+…+n1−n2 is equal to
0
−1/2
1/2
1
We have,
limn→∞ 11−n2+21−n2+31−n2+…+n1−n2=limn→∞ 1+2+3+…+n1−n2=limn→∞ n2(1−n)=−12