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Q.

limn→∞14+24+34+.....+n4n5−limn→∞1+23+33+...+n3n5

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An Intiative by Sri Chaitanya

a

15

b

130

c

0

d

14

answer is A.

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Detailed Solution

limn→∞ 14+24+34+…..n4n5−limn→∞ 13+23+….n3n5=limn→∞ 1n∑r=1n rn4−limn→∞ 1nlimn→∞ 1nrn3=∫01 x4dx−limn→∞ 1x3dx=∫01 x4dx−limn→∞ 1x3dx=x551−1∞x4401=x5501−0=15

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