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Q.

limn→∞14+24+34+.....+n4n5−limn→∞1+23+33+...+n3n5=

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a

15

b

130

c

0

d

14

answer is C.

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Detailed Solution

limn→∞14+24+34+.....n4n5−limn→∞13+23+....n3n5=limn→∞∑ r=1n1nrn4−limn→∞n2n+124n5=∫01x4dx−limn→∞1+1n24n=x5501−0  =15
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