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$lim_{n \to \infty} (\frac{1}{n} + \frac{1}{n + 1} + \dots + \frac{1}{3 n}) =$

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detailed solution

Correct option is B

limn→∞ 1n+1n+1+…+13n=limn→∞ 1n+1n+1+…+1n+2n=limn→∞ ∑k=02n 1n+k=limn→∞ 1n∑k=02n 11+k/n=∫02 dx1+x=log⁡(1+x)02=log⁡3

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