limn→∞ n2−n+1n2−n−1n(n−1) is equal to
e
e2
e-1
1
limn→∞ n2−n+1n2−n−1n(n−1)=limn→∞ n(n−1)+1n(n−1)−1n(n−1)=limn→∞ [n(n−1)]n(n−1)1+1n(n−1)n(n−1)[n(n−1)]n(n−1)1−1n(n−1)n(n−1)=limn→∞ 1+1n(n−1)n(n−1)1−1n(n−1)n(n−1)=ee−1=e2∵limn→∞ 1+1nn=e