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Correct option is D
limn→∞ 1n+1+1n+2+…+16n=limn→∞ 1n+1+1n+2+…+1n+5n=limn→∞ ∑r=15n 1n+r=limn→∞ 1n∑r=15n 11+rn∵ Lower limit of r=1∴ Lower limit of integration =limn→∞ 1n=0 ∵ Upper limit of r=5n ∴ Upper limit of integration =limn→∞ 5nn=5 from eq(i) ∫05 11+xdx=[log(1+x)]05=log6−log1=log6Similar Questions
The value of is
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