limx→−1 cos⁡2−cos⁡2xx2−|x| is equal to

limx→−1 2sin⁡(1+x)sin⁡(x−1)x2+x2limx→−1 sin⁡(x+1)x+1×sin⁡(x−1)x=2limx+1→0 sin⁡(x+1)x+1limx→1 sin⁡(x−1)x=2(1)sin⁡(−1−1)−1=2sin⁡2