limx→0 (1−cos2x)sin5xx2sin3x equals
10/3
3/10
6/5
5/6
We have,
limx→0 (1−cos2x)sin5xx2sin3x=limx→0 1−cos2xx2⋅limx→0 sin5xsin3x=limx→0 2sinxx2⋅limx→0 sin5x5x⋅3xsin3x⋅5x3x=2×53=103