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Q.

limx→π2 cot⁡x−cos⁡x(π−2x)3 is equal to

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a

1

b

π2

c

116

d

0

answer is C.

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Detailed Solution

limx→π2 cot⁡x−cos⁡x(π−2x)3 Let x=t+π2.  If x→π2⇒t→0         limt→0 sin⁡t−tan⁡t−8t3=limt→0 t−t31+,,−t−t33…−8t3=limt→0 −t32−8t3=116
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