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Q.

limx→∞   e1-e1e-x1+xx  is

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a

e(1-e)

b

e1-ee

c

ee1-e

d

e1+ee

answer is C.

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Detailed Solution

limx→∞  e1-e1e-x1+xx=1∞   then limit value is elimx→∞    e1-e1e-x1+x-1x                                                    =  e limx→∞    11-e-e1-e1+x-1x                                                        =  e limx→∞    e1-e-e1-e1+xx1+xx                                                    =  e limx→∞   e1-e1-x1+xx                                                    =  e e1-e   ..  x1+x                                                    =  e e1-e  ..   11+1x                                                    =  e e1-e
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