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a
e(1-e)
b
e1-ee
c
ee1-e
d
e1+ee
answer is C.
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Detailed Solution
limx→∞ e1-e1e-x1+xx=1∞ then limit value is elimx→∞ e1-e1e-x1+x-1x = e limx→∞ 11-e-e1-e1+x-1x = e limx→∞ e1-e-e1-e1+xx1+xx = e limx→∞ e1-e1-x1+xx = e e1-e .. x1+x = e e1-e .. 11+1x = e e1-e