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Q.

limx→1 log2⁡2xlogx⁡5 is equal to

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a

log2⁡5

b

elog2⁡5

c

e

d

0

answer is B.

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Detailed Solution

limx→1 log2⁡2xlogx⁡5=limx→1 log2⁡2+log2⁡xlogx⁡5=limx→1 1+log2⁡x1log2⁡xlog2⁡xlogx⁡5=elimx→1 log2⁡5=elog2⁡5
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