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Q.

limx→0  log1+x+x2+log1-x+x2secx  -  cos x=

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a

-1

b

1

c

0

d

2

answer is B.

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Detailed Solution

limx→0log1+x+x2+log1-x+x2secx  -  cos x=                   =limx→0   log1+x22-x21-cos2x/cosx                  =limx→0 log1+x2+x4sin x  tan  x                   =limx→0  log1+x21+x2x21+x2 x2 1+x2.1sinxx.tanxx.x2                      = 1                                          as limx→0   log1+xx=1
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